Поднятие python vpn сервера

Question

хочу создать vpn сервер на python, нашёл вот такое решение: http://voorloopnul.com/blog/a-python-proxy-in-less-than-100-lines-of-code/

но, оно работает на Python 2, а я использую python 3. Соответственно переписал немного код и получилось вот так:

import socket
from select import select
import sys
import logging
from this import s



class TcpTee:

    def __init__(self, source_port, destination):
        self.destination = destination

        self.teesock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        self.teesock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
        self.teesock.bind(('127.0.0.1', source_port))
        self.teesock.listen(200)

        # Linked client/server sockets in both directions
        self.channel = {}

    def run(self):
        while 1:
            inputready, outputready, exceptready = select([self.teesock] + self.channel.keys(), [], [])
            for s in inputready:
                if s == self.teesock:
                    self.on_accept()
                    break

                data = s.recv(4096)
                if not data:
                    self.on_close(s)
                    break

                self.on_recv(s, data)

    def on_accept(self):
        clientsock, clientaddr = self.teesock.accept()
        serversock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        try:
            serversock.connect(self.destination)
        except Exception:
            logging.exception(
                'Could not connect to server %s. Closing connection to client %s' % (self.destination, clientaddr))
            clientsock.close()
        else:
            logging.info("%r has connected", clientaddr)
            self.channel[clientsock] = serversock
            self.channel[serversock] = clientsock

    def on_close(self, sock):
        logging.info("%s has disconnected", s.getpeername())
        othersock = self.channel[sock]

        sock.close()
        othersock.close()

        del self.channel[sock]
        del self.channel[othersock]

    def on_recv(self, sock, data):
        print(data)
        self.channel[sock].send(data)



import argparse

parser = argparse.ArgumentParser()
parser.add_argument("listen_port", help="The port this process will listen on.", type=int)
parser.add_argument("server_host", help="The remote host to connect to.")
parser.add_argument("server_port", help="The remote port to connect to.", type=int)
args = parser.parse_args()

logging.basicConfig(stream=sys.stderr, level=logging.DEBUG)

tee = TcpTee(int(args.listen_port), (args.server_host, int(args.server_port)))
try:
    tee.run()
except KeyboardInterrupt:
    logging.info("Ctrl C - Good Bye")
    sys.exit(1)

Изначально вообще ничего не произошло при запуске, но после небольших правок запустилось с ошибкой:

The Zen of Python, by Tim Peters

Beautiful is better than ugly.
Explicit is better than implicit.
Simple is better than complex.
Complex is better than complicated.
Flat is better than nested.
Sparse is better than dense.
Readability counts.
Special cases aren't special enough to break the rules.
Although practicality beats purity.
Errors should never pass silently.
Unless explicitly silenced.
In the face of ambiguity, refuse the temptation to guess.
There should be one-- and preferably only one --obvious way to do it.
Although that way may not be obvious at first unless you're Dutch.
Now is better than never.
Although never is often better than *right* now.
If the implementation is hard to explain, it's a bad idea.
If the implementation is easy to explain, it may be a good idea.
Namespaces are one honking great idea -- let's do more of those!
usage: vpn.py [-h] listen_port server_host server_port
vpn.py: error: the following arguments are required: listen_port, server_host, server_port

Process finished with exit code 2

Никогда с таким не сталкивался, как это можно исправить? Или может у кого уже есть данная реализация

БЛОГ НА HUSL

Поднятие python vpn сервера

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