Argument in bash script duplicates output

Question

i wrote a Bash shell script which prints out information about file or directory, provided in argument, but something went wrong, and if i put dir in argument, it does not show me the list of files

#!/bin/bash
for path in $1*
do
if [ -d $1 ]
then
        echo "File: '$1'"
        echo "Type: `stat -c%F $1`"
        echo "Permissions: (`stat -c%a/%A $1`)"
        echo "-----------"
elif [ -f $1 ]
then
        echo "File: '$1'"
        echo "Type: `stat -c%F $1`"
        echo "Permissions: (`stat -c%a/%A $1`)"
        echo "-----------"
fi
done

Answer 1

Correct Answer

#!/bin/bash
for path in $1*
do
if [ -d $path ]
then
        echo "File: '$path'"
        echo "Type: `stat -c%F $path`"
        echo "Permissions: (`stat -c%a/%A $path`)"
        echo "-----------"
elif [ -f $path ]
then
        echo "File: '$path'"
        echo "Type: `stat -c%F $path`"
        echo "Permissions: (`stat -c%a/%A $path`)"
        echo "-----------"
fi
done

БЛОГ НА HUSL

Argument in bash script duplicates output

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