Выдаёт ошибку(Parse error: syntax error, unexpected '}' in D:\Programs\OpenServer\domains\forer\index.php on line 21)
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Document</title>
<link rel="stylesheet"
href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css" integrity="sha384-
9aIt2nRpC12Uk9gS9baDl411NQApFmC26EwAOH8WgZl5MYYxFfc+NcPb1dKGj7Sk" crossorigin="anonymous">
<link rel="stylesheet" href="css/sign.css">
</head>
<body>
<?php
require('connect.php');
if(isset($_POST['username']) && isset($_POST['password'])){
$username = $_POST['username'];
$email = $_POST['email'];
$password = $_POST['password'];
$query = "INSERT INTO users (username, password, email) VALUES ('$username', '$email',
'$password')";
$result = mysqli_master_query($connection, $query);
if($result){
$smsg = "Регистрация прошла успешна"
}
else{
$fsmsg = "Ошибка";
}
}
?>
<div class="container">
<form class="form-signin" method="POST">
<h2>Регистрация</h2>
<?php if(isset($smsg)){ ?><div class="alert alert-success" role="alert"> <?php echo $smsg; ?>
</div><?php}?>
<?php if(isset($fsmsg)){ ?><div class="alert alert-danger" role="alert"> <?php echo $fsmsg; ?
> </div><?php}?>
<input type="text" name="username" class="form-control" placeholder="Username" required>
<input type="email" name="email" class="form-control" placeholder="Email" required>
<input type="password" name="password" class="form-control" placeholder="Password" required>
<button class="btn btn-lg btn-primary btn-block" type="submit">Register</button>
</form>
</div>
</body>
</html>
Ответы (1 шт):
Автор решения: humster_spb
→ Ссылка
- У Вас после
$smsg = "Регистрация прошла успешна"нет точки с запятой. - Во втором
<?php if(isset($fsmsg)){ ?><div class="alert alert-danger" role="alert"> <?php echo $fsmsg; ? > </div><?php}?>некорректно написан закрывающий тег php