Gulp Ошибка Cannot Get

let project_folder = "dist";
let source_folder = "src";

let path = {
  build: {
    html: project_folder + "/",
    css: project_folder + "/css/",
    js: project_folder + "/js/",
    img: project_folder + "/img/",
    logo: project_folder + "/logo/",
    fonts: project_folder + "/Fonts/",
    video: project_folder + "/Video/",
  },

  src: {
    html: source_folder + "/*.html",
    css: source_folder + "/scss/main.scss",
    js: source_folder + "/js/main.js",
    img: source_folder + "/img/**/*.{jpg}",
    logo: source_folder + "/logo/",
    fonts: source_folder + "/Fonts/*.ttf",
    video: source_folder + "/Video/",
  },
  watch: {
    html: source_folder + "/**/*.html",
    css: source_folder + "/scss/**/*.scss",
    js: source_folder + "/js/**/*.js",
    img: source_folder + "/img/**/*.{jpg}",
    logo: source_folder + "/logo/",
    video: source_folder + "/Video/",
  },

  clean: "./" + project_folder + "/"
};


let { src, dest } = require('gulp'),
  gulp = require('gulp'),
  browsersync = require("browser-sync").create(),
fileinclude = require("gulp-file-include");
  
  
  function browserSync (params) {
      browsersync.init({
        server:{
          baseDir: "./" + project_folder + "/"
        },
        port: 8080,
        notify: false
      });
  }

  function html(){
      return src(path.src.html)
        .pipe(fileinclude())
      .pipe(dest(path.build.html))
      .pipe(browsersync.stream())
  }

  let build = gulp.series(html);
  let watch = gulp.parallel(build, browserSync);

  exports.html = html;
  exports.build = build;
  exports.watch = watch;
  exports.default = watch;