Как в PyQt5 правильно прописать недостающий атрибут?

Элементарная невнимательность. Вопрос закрыт

main.py

import sys
from PyQt5.QtWidgets import QMainWindow, QApplication
from PyQt5.uic import loadUi
from PyQt5.QtSerialPort import QSerialPort, QSerialPortInfo
from PyQt5.QtCore import QIODevice


class New(QMainWindow):
    def __init__(self):
        super(New, self).__init__()

        loadUi("Arduino_GUI.ui", self)
        self.setWindowTitle('New')

        self.openB.clicked.connect(self.onOpen)
        self.closeB.clicked.connect(self.onClose)
        self.ledC.stateChanged.connect(self.ledControl)

        self.serial = QSerialPort()
        self.serial.setBaudRate(115200)
        portList = []
        ports = QSerialPortInfo().availablePorts()
        for port in ports:
            portList.append(port.portName())
        print(portList)
        self.comL.addItems(portList)

    def onOpen(self):
        print('on')
        self.serial.setPortName(self.comL.currentText())
        self.serial.open(QIODevice.ReadWrite)

    def onClose(self):
        print('close')
        self.serial.close()

    def serialSend(self, data):
        txs = ''
        for val in data:
            txs += str(val)
            txs += ','
        txs = txs[:-1]
        txs += ';'
        self.serial.write(txs.encode())

    def ledControl(self, val):
        if val == 2: val = 1;
        print('led')
        self.serialSend([0, val])

    def closeEvent(self, e):
        super().closeEvent(e)


if __name__ == '__main__':
    app = QApplication(sys.argv)
    window = New()
    window.show()
    sys.exit(app.exec_())