Selenium не может найти путь к кнопке "лайка" в instagram

Путь к кнопке "лайка" копировал прямо со странички instagram в браузере и по этому не пойму в чем тут может быть проблема? ведь когда я в верхней части кода искал username и password нашло без проблем.

    from selenium import webdriver
    from selenium.webdriver.common.keys import Keys
    from webdriver_manager.chrome import ChromeDriverManager
    from auth_data import username, password
    import time
    import random


def hashtag_search(username, password, hashtag):

    browser = webdriver.Chrome(ChromeDriverManager().install())

    try:
        browser.get('https://www.instagram.com')
        time.sleep(random.randrange(3, 5))

        username_input = browser.find_element_by_name('username')
        username_input.clear()
        username_input.send_keys(username)

        time.sleep(2)

        password_input = browser.find_element_by_name('password')
        password_input.clear()
        password_input.send_keys(password)

        password_input.send_keys(Keys.ENTER)
        time.sleep(5)

        try:
            browser.get(f'https://www.instagram.com/explore/tags/{hashtag}/?hl=ru')
            time.sleep(5)

            for i in range(1, 4):
                browser.execute_script("window.scrollTo(0, document.body.scrollHeight);")
                time.sleep(random.randrange(3, 5))

            hrefs = browser.find_elements_by_tag_name('a')
            posts_urls = [item.get_attribute('href') for item in hrefs if "/p/" in item.get_attribute('href')]


            for url in posts_urls:
                try:
                    browser.get(url)
                    time.sleep(3) #3
                    like_button = browser.find_element_by_xpath("/html/body/div[6]/div[2]/div/article/div/div[3]/div/div/section[1]/span[1]/button")
                    like_button.click()

                    time.sleep(random.randrange(80, 100))
                except Exception as ex:
                    print(ex)

            browser.close()
            browser.quit()

        except Exception as ex:
            print(ex)
            browser.close()
            browser.quit()

    except Exception as ex:
        print(ex)
        browser.close()
        browser.quit()

hashtag_search(username, password, 'surfing')